3m^2+72=30m

Solution for 3m^2+72=30m equation:

3m^2+72=30m

We move all terms to the left:

3m^2+72-(30m)=0

a = 3; b = -30; c = +72;
Δ = b2-4ac
Δ = -302-4·3·72
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6}{2*3}=\frac{24}{6}
=4
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6}{2*3}=\frac{36}{6}
=6
$